0
import vlc

p = vlc.MediaPlayer("https://www.youtube.com/watch?v=7ailmFB38Rk")
p.play()

gives me this error

[00007f97a80030c0] http stream error: local stream 1 error: Cancellation (0x8)

I was told this is causes if the link is invalid or broken, both of these are not the cases because using regular vlc to play the video works perfectly

Also, if it is somehow not possible to play the video, I only need to play the audio so that will also be of help.

RandomPersonOnline
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1 Answers1

2

use pafy


# importing vlc module 
import vlc 
  
# importing pafy module 
import pafy 
  
# url of the video 
url = "https://www.youtube.com/watch?v = vG2PNdI8axo"
  
# creating pafy object of the video 
video = pafy.new(url) 
  
# getting best stream 
best = video.getbest() 
  
# creating vlc media player object 
media = vlc.MediaPlayer(best.url) 
  
# start playing video 
media.play()
RandomPersonOnline
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