0

[EDIT]: I am a newbie in using winscp get command.

Lets say I have multiple files in this format

ABC_ddMMyyyy.mmss.123.xml and ABC_ddMMyyyy.mmss.234.xml

where ddMMyyyy represent today's date

What is the correct command to retrieve all the files?

I figure out that using this

get /remote_path/*.xml C:\Users\christ\Documents\ is not a good idea because I only want to retrieve today date.

Thanks in advance

Norman
  • 1
  • 1

0 Answers0