Python / Spyder - Undefined variable error, when variable is defined and shown in the environment. Code works even with the error

Question

I am getting a strange error when defining variables in Python 4.1.5 (IDE:Spyder). However, even with the error, the code runs without any issues!

As you can see, the variable social_cost_of_carbon is stored as a variable, but I keep getting that error as show in picture 1 (the error writes: Undefined name 'social_cost_of_carbon' (Pyflakes E)

I feel that the way that i declare those variables might be the reason:

def convert_to_var(df):
    desc = []
    val = []  
    
    for i,row in df.iterrows():
        desc.append(i)
        val.append(row) 
        
    return dict(val)

val_dict = convert_to_var(IA)
locals().update(val_dict)

Since the code runs without any problems, I am not doing anything to resolve this. Do I need to worry and fix this, or do I just let it be and continue without dealing with the error since the code runs smoothly?

Thanking you in advance.

score 1 · Accepted Answer · answered Nov 17 '20 at 04:13

1

(Spyder maintainer here) As you guessed, the problem is that you're creating your variable dynamically with this line in your code:

locals().update(val_dict)

Since our linter can't find where that variable is properly declared, it reports that it's undefined. But it's safe for you to ignore that message.

Note: For now it's not possible to hide linter warnings. However, in a future version we'll provide a way to do that by adding a comment at the end of a line of the form # noqa.

answered Nov 17 '20 at 04:13

Carlos Cordoba

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Thanks for your answer Carlos, it really clear things up. Do you have an expectation of when this future version will be available? – sophocles Nov 17 '20 at 13:57
Most probably in our 4.2.2 version, to be released in February 2021. – Carlos Cordoba Nov 17 '20 at 14:24
Excellent - would love to see the little red dots disappear from my code =] – sophocles Nov 17 '20 at 14:28
I was presuming that, that's why I left my note at the end. – Carlos Cordoba Nov 17 '20 at 14:30

Python / Spyder - Undefined variable error, when variable is defined and shown in the environment. Code works even with the error

1 Answers1