What error in my code I have which cause exceptions ignored?

Question

I am Implementing some program error exception catching and it's not getting to work properly thus I have seen any error in my code and compiler is also not showing any warnings and error. The programs build successfully but ignored the exceptions.

#include <iostream>
#include <string>
using namespace std;

void wrongUsage()
{
   bool erroCode = true;
   bool errorMessge = true;
   bool stringError = true;

   if(erroCode)
   {
      throw 7;
   }else if (errorMessge)
   {
      throw "Something went wrong in Character message";
   }else if(stringError)
   {
      throw string ("Something else wrong happened in the string area");
   }
}

void programErrorExceptions()
{
   void wrongUsage();
}

int main()
{
   try {
      programErrorExceptions();
   }
   catch (int err)
   {
      cout << "Code Exception occurred: " << err << '\n';
   }
   catch (char const *err)
   {
      cout << "Msg Exception occurred: " << err << '\n';
   }
   catch (string &err)
   {
      cout << "Strmsg Exception occurred: " << err << '\n';
   }

   return 0;
}

What do you mean by "ignored the exceptions"? What happened, exactly? — Asteroids With Wings, Nov 10 '20 at 16:17

score 2 · Accepted Answer · answered Nov 10 '20 at 16:19

2

correct the following

void programErrorExceptions()
{
   void wrongUsage();
}

to

void programErrorExceptions()
{
   wrongUsage();
}

answered Nov 10 '20 at 16:19

Harry

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@AsteroidsWithWings yes it fixed the Issue :D – Tahir Nov 10 '20 at 16:20

What error in my code I have which cause exceptions ignored?

1 Answers1