FastAPI - Set the url or path for the Request object

Question

I have a function that looks like this:

@app.middleware("http")
async def process_api_event(request: Request, call_next):
     url = request.url
     path = request.url.path 
     # request.__setattr__('url', 'sample_url')
     # request.url.__ setattr__('path', 'sample_path')

In the above function, depending on the situation I would like to change the request url, or path. I tried request.__setattr__('url', 'sample_url') and request.url.__ setattr__('path', 'sample_path') as shown above but I wasn't able to do it due to AttributeError: can't set attribute error. I read through the FastAPI and Starlette documentation, but couldn't really find info that I needed in this case. Any help would be greatly appreciated!

Why do you want to change the ***`url`*** attribute? – JPG Oct 30 '20 at 03:53 — JPG, Oct 30 '20 at 03:53

score 0 · Accepted Answer · answered Oct 30 '20 at 08:35

request.url is a property that gets _url attribute, so you can set _url (but request.scope and request.base_url will not change)

from starlette.datastructures import URL

@app.middleware("http")
async def process_api_event(request: Request, call_next):
    request._url = URL('sample_url')
    print(request.url)
    ...

FastAPI - Set the url or path for the Request object

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