Pasting bash script to console without exit calls

Question

I often "debug" bash scripts by opening them in the text editor and pasting them to the console, not line by line but "logical unit by logical unit".

Sometimes I then have these constructs:

if [ ! -f $inputFile ]; then
    echo "You must specify an existing file, milord!"
    exit 5
fi

However, pasting that to the console (without a valid $inputFile of course) immediately closes my console.

Is there any way to circumvent that?

[trap](https://tldp.org/LDP/Bash-Beginners-Guide/html/sect_12_02.html) — 0stone0, Oct 29 '20 at 15:10
Maybe this could help you: [how to trap errors inside the if statement](https://stackoverflow.com/questions/13103701/how-to-trap-errors-inside-the-if-statement) — 0stone0, Oct 29 '20 at 15:15

score 2 · Accepted Answer · answered Oct 29 '20 at 15:11

2

One hack you could try would be to just make exit an alias:

alias exit='echo exiting...'

Your sample code now will just print exiting... and move on.

When you're done with your debugging session, you need to just:

unalias exit

answered Oct 29 '20 at 15:11

Costi Ciudatu

1

One problem with this is that the code may continue running after where it normally would have exited. So be careful! – Gordon Davisson Oct 29 '20 at 16:22
@GordonDavisson correct, thanks for pointing that out. – Costi Ciudatu Oct 29 '20 at 17:12

1 Answers1