Map over the collection, safely destructuring and then transforming each element. These are the semantics that I would expect for an expression like
val b = a map (((x, y), u) => ((y, x), u)))
Unfortunately, there is no concise syntax to achieve these semantics in Scala.
Instead, you have to destructure yourself:
val b = a map { p => ((p._1._2, p._1._1), p._2) }
One might be tempted to use a value definition for destructuring:
val b = a map { p => val ((x,y), u) = p; ((y, x), u) }
However, this version is no more safe than the one that uses explicit pattern matching. For this reason, if you want the safe destructuring semantics, the most concise solution is to explicitly type your collection to prevent unintended widening and use explicit pattern matching:
val a: List[((Int, Int), Int)] = // ...
// ...
val b = a map { case ((x, y), u) => ((y, x), u) }
If a
's definition appears far from its use (e.g. in a separate compilation unit), you can minimize the risk by ascribing its type in the map call:
val b = (a: List[((Int, Int), Int)]) map { case ((x, y), u) => ((y, x), u) }