QT + XSB prolog: "read access violation at 0x0"

Asked Oct 28 '20 at 05:16

Active Nov 02 '20 at 08:34

Viewed 52 times

I want to use XSB prolog in QT application. I wrote:

#include <QtWidgets/QApplication>
#include "mainwindow.h"
#include "cinterf.h"

int main(int argc, char *argv[])
{
    /* Initialize xsb */
    xsb_init_string((char*)("c:/Program Files (x86)/XSB -n"));
    char s[100] = "consult('g:/develop/qt/paid/kb').";
    int r = xsb_command_string(s);

    QApplication a(argc, argv);
    MainWindow w;
    w.show();

    return a.exec();
}

But it crashes with an error message "read access violation at 0x0 ...". What is the problem and how to fix it? ]

edited Nov 02 '20 at 08:34

false

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asked Oct 28 '20 at 05:16

Иван Коданев

1

The error occurs in xsb_command_string function. – Иван Коданев Oct 28 '20 at 05:18
Suggest that you ask on the QT forums concerning xsb interfaces. – peter.cyc Oct 28 '20 at 13:13
Does the exception also occur when you remove the Qt parts? You could use `std::cout` in the beginning. Then you know if the error is related to Xsb or Qt – lambda.xy.x Oct 28 '20 at 14:11
I did not test it. I think it's no matter what C++ code is around XSB calls. It's just the problem within XSB I guess. – Иван Коданев Oct 29 '20 at 07:29

QT + XSB prolog: "read access violation at 0x0"

0 Answers0