Match the part of a string in the array using JavaScript

Question

I have a single dimensional array with the below format,

let e = ["CGST:20", "SGST:20", "IGST:20", "CESS:20", "GSTIncentive:20", "GSTPCT:20"].map(i=>i.trim());

And want to match the specific string in the array, say for example, match the part of the string "IGST" in the "IGST:20".

I have tried in the below way, but it always matching the first key in the array,

if(/^IGST:/.test(e)){
  console.log("matched")
} else {
  console.log("Not matched")
}

*"but it always matching the first key in the array"* No, it's always matching the array's contents after they've been converted to a string. — T.J. Crowder, Oct 27 '20 at 12:08
@T.J.Crowder - can you please suggest better approach to solve this? — vishnu, Oct 27 '20 at 12:11
Does this answer your question? [In javascript, how do you search an array for a substring match](https://stackoverflow.com/questions/4556099/in-javascript-how-do-you-search-an-array-for-a-substring-match) — Heretic Monkey, Oct 27 '20 at 12:19

score 1 · Accepted Answer · answered Oct 27 '20 at 12:11

If your goal is to find out if that regular expression matches any entry in the array, you can use the some function for that:

if (e.some(entry => /^IGST:/.test(entry)) {
    console.log("matched")
} else {
    console.log("Not matched")
}

If you want to find the matching entry, use find instead. If you want its index, use findIndex.

Details on MDN.

1 Answers1