Is it possible to use a custom serializer/deserializer for a type by default in spring?

Question

I have a type from a third party library (JSONB from jooq) that I've written a custom serializer/deserializer for:

@JsonComponent
public class JSONBSerializer extends JsonSerializer<JSONB> {
    @Override
    public void serialize(JSONB jsonb, JsonGenerator jsonGenerator, SerializerProvider serializerProvider) throws IOException {
        jsonGenerator.writeString(jsonb.toString());
    }
}

@JsonComponent
public class JSONBDeserializer extends JsonDeserializer<JSONB> {
    @Override
    public JSONB deserialize(JsonParser jsonParser, DeserializationContext deserializationContext) throws IOException, JsonProcessingException {
        return JSONB.valueOf(jsonParser.getValueAsString());
    }
}

I am wondering if there is a way to tell spring or jackson to use these by default without having to annotate every JSONB field in the project with @JsonSerialize(using = JSONBSerializer.class) and @JsonDeserialize(using = JSONBDeserializer.class)?

score 1 · Accepted Answer · answered Oct 28 '20 at 22:58

You need to create new com.fasterxml.jackson.databind.module.SimpleModule instance and register all custom serialisers and deserialisers. Next, you need to check out how to register new custom module in your version of Spring Boot.

@Bean
public SimpleModule jooqModule() {
    SimpleModule jooqModule = new SimpleModule();
    jooqModule.addSerializer(JSONB.class, new JSONBSerializer());
    jooqModule.addDeserializer(JSONB.class, new JSONBDeserializer());
}

Take a look at:

Is it possible to use a custom serializer/deserializer for a type by default in spring?

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