Copying strings to an array

Question

In my code's output I find that the strings I am printing are all (null) even though I input count strings of characters < 31.

char name[31];
char *names[32];
int count = 5;
for (int i =0; i<count;i++) {
        scanf("%s",name);
        names[i]=(char*)malloc(strlen(name)+1);
        strcpy(names[i],name);
    }

for (int i =0; i<count;i++) {
    printf("%d: %s\n",i+1,names[count]);
}

Answer 1

Maybe you should use names[i] in stead of names[count]

for (int i = 0; i < count; i++) {
    printf("%d: %s\n", i+1, names[i]);
}

Answer 2

you're indexing names with count but your code initialize string only up to count - 1. Changing printf this way:

printf("%d: %s\n",i+1,names[i]);

should do the trick.

Answer 3

Your error is in the printf function, you need to modify it in this way:

printf("%d: %s\n",i+1,names[count]); => printf("%d: %s\n",i+1,names[i]);