Compare Date and Time range with Java

Question

I have this input:

{
  "MONDAY" : "02:39:00"
}

Which is a DAY and time that needs to compared to

  "availability" : {
    "SUNDAY" : {
      "from" : "00:00",
      "to" : "10:00"
    },
    "MONDAY" : {
      "from" : "00:00",
      "to" : "10:00"
    }
  }

What's the best way to compare if the availability in fact contains a DAY in which the time in the query 02:39:00 is within.

As such, it can be represented in Java-form:

boolean isOpen = checkIfOpen("MONDAY", "02:39:00", availabilityJSONObject);

And which in this case, the value of isOpen would be true.

Are you using a JSON library? (for example Jackson or Gson?) — Ole V.V., Oct 16 '20 at 19:24

score 1 · Answer 1 · answered Oct 16 '20 at 19:11

1

I would approach this problem by using two maps with key as day and from time as value for the first map and to time as value for the second map.

And check if the time falls between this time.

You could use gson to convert the json to java objects.

answered Oct 16 '20 at 19:11

Pranav balu

126
1
5

score 1 · Accepted Answer · answered Oct 16 '20 at 19:44

As Pranav balu already said, use Java objects/data structures for your data. Use a JSON library like Jackson or Gson for converting your JSON input to Java types. You will need a Java type for the daily availability range. For example:

public class AvailabilityRange {

    LocalTime opens;
    LocalTime closes;
    
    public AvailabilityRange(String from, String to) {
        opens = LocalTime.parse(from);
        closes = LocalTime.parse(to);
    }
    
    public boolean inRange(String timeString) {
        LocalTime time = LocalTime.parse(timeString);
        return (! time.isBefore(opens)) && time.isBefore(closes);
    }
}

I have provided a convenience constructor and a convenience method that accept String arguments. You may want a constructor and a method that accept LocalTime, or both.

Example use:

        Map<DayOfWeek, AvailabilityRange> availability
                = new EnumMap<DayOfWeek, AvailabilityRange>(
                        Map.of(DayOfWeek.SUNDAY, new AvailabilityRange("00:00", "10:00"), 
                                DayOfWeek.MONDAY, new AvailabilityRange("00:00", "10:00")));
        
        String dayString = "MONDAY";
        String timeString = "02:39:00";
        
        boolean isOpen;
        AvailabilityRange availabilityForDay
                = availability.get(DayOfWeek.valueOf(dayString));
        if (availabilityForDay == null) {
            isOpen = false;
        } else {
            isOpen = availabilityForDay.inRange(timeString);
        }
        
        System.out.println("Is open? " + isOpen);

Output:

Is open? true

I am exploiting the fact that your time strings are in ISO 8601 format, and LocalTime parses this format as its default, that is, without any explicit formatter. The seconds are optional in the format, so both 00:00 and 02:39:00 are parsed.

Compare Date and Time range with Java

2 Answers2