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3d-surface plot of the Ploty (python 3.x, Jupyter) worked properly in my case. However, when I set the opacity of the surface, the surface seemed to be transparent and disapear. In this case, I set the opacity as 0.9.

import plotly.graph_objects as go
import numpy as np
z1 = np.array([
    [8.83,8.89,8.81,8.87,8.9,8.87],
    [8.89,8.94,8.85,8.94,8.96,8.92],
    [8.84,8.9,8.82,8.92,8.93,8.91],
    [8.79,8.85,8.79,8.9,8.94,8.92],
    [8.79,8.88,8.81,8.9,8.95,8.92],
    [8.8,8.82,8.78,8.91,8.94,8.92],
    [8.75,8.78,8.77,8.91,8.95,8.92],
    [8.8,8.8,8.77,8.91,8.95,8.94],
    [8.74,8.81,8.76,8.93,8.98,8.99],
    [8.89,8.99,8.92,9.1,9.13,9.11],
    [8.97,8.97,8.91,9.09,9.11,9.11],
    [9.04,9.08,9.05,9.25,9.28,9.27],
    [9,9.01,9,9.2,9.23,9.2],
    [8.99,8.99,8.98,9.18,9.2,9.19],
    [8.93,8.97,8.97,9.18,9.2,9.18]
    ])
z2 = z1 + 1
z3 = z1 - 1
fig = go.Figure(data=[
    go.Surface(z=z1),
    go.Surface(z=z2, showscale=False, opacity=0.9),
    go.Surface(z=z3, showscale=False, opacity=0.9)
    ])
fig.show()

enter image description here

If you look at the image above, only trace 0 is shown. trace 1 and trace 2 are transparent when I set the opacity to 0.9 and it should not be like this. (trace 2 still can be annotated in the image) Anyone has a solution for this issue.

Kim Tang
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Tatchaphon Leelaprachakul
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1 Answers1

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Unfortunately, i couldn't reproduce your error while running the same code as yours.

enter image description here

other issue might be z2 and z3 values overites to z1. Try to rerun in new environment.

jgrt
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  • Thank you very much. Here is actually where my problem is. I am sorry for not state it correctly. I do not think that is the coding problem. The code used to be working. However, after I run it several times the opacity was errored as I was mentioned. I have been tried restarted my laptop and retry, still not working. Do you have any suggestions? – Tatchaphon Leelaprachakul Oct 16 '20 at 03:18