PyQt- Button Manipulation

Question

How can I use a Qt designer object name in the form 'boxXY' where X is the row value and Y value is the column value for a python 2D list;

import sys,os
from PyQt5 import QtCore, QtGui, uic
rowsColumns=[[],[],[],[],[],[],[],[],[],[]]##Current grid values

allScreens=uic.loadUiType("newSudokuScreens.ui")[0]

class aWindowClass(QtGui.QMainWindow, allScreens):
    def __init__(self, parent=none):
        QtGui.QMainWindow.__init__(self, parent)
        self.setupUi(self)
        self.GPScreen.setVisible(True)
        self.CPScreen.setVisible(False)
        self.DSScreen.setVisible(False)
        self.HTPScreen.setVisible(False)
        self.MMScreen.setVisible(False)
        self.NPSUScreen.setVisible(False)
        self.PSIScreen.setVisible(False)
        self.RUPScreen.setVisible(False)
        self.SPUScreen.setVisible(False)
        self.box00.clicked.connect(self.findRowColumn)
    
    def findRowColumn(self):
        row=#4th character of button name
        column=#5th character of button
        numberWanted=int(input('enter value wanted')) #is part of UI but making row and column value work will help make this work
        rowsColumns[row][column]=numberWanted
    
for i in range(0,9):
    for j in range(0,9):
        rowsColumns[i].append(0) #fill grid with necessary 81 spaces for sudoku
    print(rowsColumns[i])
    
app=QtGui.QApplication(sys.argv)
aWindow=aWindowClass(None)
aWindow.show()
app.exec_()

So for an example if button box56 is clicked I want to pass box56 as a variable then in the procedure when a box is clicked row will be set as 5 and column will be set as 6 then append it to that place in the 2D list.

Thanks in advance.

Unsure whether this will answer your problem, but in the code of the slot, you can use the `sender` method to get a reference to the object that send the clicked message. From the object, it is easy to extract the title or any other value. — Serge Ballesta, Oct 14 '20 at 13:08
Of course. But you should first put your code in text in the question itself so that I can copy and paste it. — Serge Ballesta, Oct 14 '20 at 15:30

score 0 · Accepted Answer · answered Oct 15 '20 at 08:20

0

Independently of the solution proposed by @eyllanesc, it is easy from a slot to find the object that sent a signal and its properties.

Here you could do:

def findRowColumn(self):
    button_name = self.sender().text()   # gets the text of the button
    row = int(button_name[3]) # 4th character of button name
    column = int(button_name[4]) # 5th character of button
    numberWanted = int(
        input('enter value wanted'))  # is part of UI but making row and column value work will help make this work
    rowsColumns[row][column] = numberWanted

answered Oct 15 '20 at 08:20

Serge Ballesta

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Hi @Serge Ballesta thanks for an answer but unfortunately the answer given isn't quite what I need as self.sender().text() gives the text inside the object not the actual name of the object, and I can't have the button name in the text so is there a similar or is there not actually a way to pass the object name, the button clicked to run the procedure – Samuel W Oct 19 '20 at 12:43
@SamuelW Maybe what you want is `objectName` and not `text`. An other useable property is `windowTitle` – Serge Ballesta Oct 20 '20 at 05:21

PyQt- Button Manipulation

1 Answers1