How to enforce that 0 not equal to 00 or 000 Python 3.8.5

Question

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i = 0

x = 00

list1 = [(3000,2,1), (9000,0,8), (4,5,6, 000)]

a = (len(list1))

while (True):

if (x in list1[i]):

    print ( list1[i])

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This will print: (9000, 0, 8) and (4, 5, 6, 0). This is false result-- How to enforce digit-count or other workaround to avoid this.

Pycharm 2020.2

`001` and `1` are the same number. If leading-zeroes are important for you, you want strings, not numbers. — Blackhole, Oct 13 '20 at 18:11
i.e. 0000 int8_t while 00000000 is int16_t. And 00 vector in 2d matrix while 000 vector in 3d matrix. — user176105, Oct 13 '20 at 19:03

score 0 · Answer 1 · answered Oct 13 '20 at 21:44

00 and 000 are the exact same as 0, just as 001 and is the same as 1 (I should mention this is in math, not python). You'd need to use strings to keep the leading zeros.

This'll work:

i = 2
x = "000"

list1 = [("3000", "2", "1"), ("9000", "0", "8"), ("4", "5", "6", "000")]

if x in list1[i]:
    print(list1[i])

How to enforce that 0 not equal to 00 or 000 Python 3.8.5

1 Answers1