As per this question - template argument deduction with strongly-typed enumerations - it seems challenging - if not impossible - to get strongly typed enumerators to participate in overload resolution.
if we have the following
#include <string>
#include <iostream>
void ExternalFunction(const std::string& tag, int value)
{
std::cout << tag << " - (int) " << value << std::endl;
}
void ExternalFunction(const std::string& tag, double value)
{
std::cout << tag << " - (double) " << value << std::endl;
}
void ExternalFunction(const std::string& tag, const std::string& value)
{
std::cout << tag << " - (string) " << value << std::endl;
}
class Wrapper
{
public:
virtual void DoSomething() = 0;
};
template <typename variable_type>
class VariableWrapper : public Wrapper
{
public:
VariableWrapper(variable_type variable) : variable(variable) {}
void DoSomething() override
{
ExternalFunction("tag", variable);
}
variable_type& variable;
};
template <typename enumerator, typename convert_to_string>
class EnumWrapper : public VariableWrapper<enumerator>
{
public:
EnumWrapper(enumerator& variable, convert_to_string encoder) : VariableWrapper<enumerator>(variable), encoder(encoder) {}
void DoSomething() override
{
ExternalFunction("tag", encoder(VariableWrapper<enumerator>::variable));
}
convert_to_string encoder;
};
enum class StronglyTyped
{
A,
B,
C
};
int main()
{
StronglyTyped e = StronglyTyped::A;
Wrapper* wrapper = new EnumWrapper(e, [](StronglyTyped S)->std::string{return "Test";});
wrapper->DoSomething();
}
if we try to run this - http://coliru.stacked-crooked.com/a/d555c4e3300ab05d - we get the errors
main.cpp: In instantiation of 'void VariableWrapper<variable_type>::DoSomething() [with variable_type = StronglyTyped]':
main.cpp:31:14: required from here
main.cpp:33:29: error: no matching function for call to 'ExternalFunction(const char [4], StronglyTyped&)'
33 | ExternalFunction("tag", variable);
| ~~~~~~~~~~~~~~~~^~~~~~~~~~~~~~~~~
main.cpp:4:6: note: candidate: 'void ExternalFunction(const string&, int)'
4 | void ExternalFunction(const std::string& tag, int value)
| ^~~~~~~~~~~~~~~~
main.cpp:4:51: note: no known conversion for argument 2 from 'StronglyTyped' to 'int'
4 | void ExternalFunction(const std::string& tag, int value)
| ~~~~^~~~~
main.cpp:9:6: note: candidate: 'void ExternalFunction(const string&, double)'
9 | void ExternalFunction(const std::string& tag, double value)
| ^~~~~~~~~~~~~~~~
main.cpp:9:54: note: no known conversion for argument 2 from 'StronglyTyped' to 'double'
9 | void ExternalFunction(const std::string& tag, double value)
| ~~~~~~~^~~~~
main.cpp:14:6: note: candidate: 'void ExternalFunction(const string&, const string&)'
14 | void ExternalFunction(const std::string& tag, const std::string& value)
| ^~~~~~~~~~~~~~~~
main.cpp:14:66: note: no known conversion for argument 2 from 'StronglyTyped' to 'const string&' {aka 'const std::__cxx11::basic_string<char>&'}
14 | void ExternalFunction(const std::string& tag, const std::string& value)
| ~~~~~~~~~~~~~~~~~~~^~~~~
Is it possible to get the strongly typed enumerator to participate in the overload resolution? I don't want to remove the strongly typing - which does remove this issue - as i will then have to use unique names between multiple enums
EDIT: i have removed the std::to_string from the question and updated the code accordingly as it was incorrectly being focused on.