Find regular polygon's vertices

Question

I have some properties defined by the user, and then I want use them to automatically generate a regular polygon. The properties are centre x, centre y, radius and number of vertices. I would like to know how to calculate the x and y coordinates of all vertices of a regular polygon. I've already tried to do as Calculate coordinates of a regular polygon's vertices discussion. But it always gives me thw wrong coordinates. My current code is as follows (C++):

#define DOUBLE(a) ((a)*(a))

...

if(radius <= 0 || vertices < 3)
  return NULL;

Polygon* poly = new Polygon;

double angle = DOUBLE(M_PI) / vertices;

for(long i = 0; i < vertices; i++)
{
  double a = (angle * i);

  poly->add(centerX + radius * cos(a), centerY + radius * sin(a));
}

return poly;

You also need the angle of the first vertex. – Ignacio Vazquez-Abrams Jun 21 '11 at 18:12 — Ignacio Vazquez-Abrams, Jun 21 '11 at 18:12

Alnitak · Accepted Answer · 2011-06-21T18:20:31.543

8

There's an error in your angle calculation.

The angle between each vertex should be 2 * M_PI / vertices.

Obviously your macro:

#define DOUBLE(a) ((a)*(a))

is incorrect.

However in C++ you really shouldn't use macros for such trivial operations anyway - it should at the very most be an inline function, or just the direct formula given above.

edited Jun 21 '11 at 18:20

answered Jun 21 '11 at 18:09

Alnitak

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That was it, I think I'm going crazy – Wanderson Silva Jun 21 '11 at 18:21
@belisarius Okay, It's just 'cause I'm new as user. – Wanderson Silva Jun 22 '11 at 02:51

score 1 · Answer 2 · answered Jun 21 '11 at 18:12

1

Try

#define DOUBLE(a) ((a) + (a))

or

#define DOUBLE(a) (2 * (a))

You are defining SQUARE(a) under a false identity.

answered Jun 21 '11 at 18:12

John R. Strohm

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Find regular polygon's vertices

2 Answers2