How can i find the first n negative integers by using an array

Question

I wanted to find a way i can the first n negative integers so if i put in 7 it would produce [-1,-2,-3,-4,-5,-6,-7]

import stdio
import sys

n = int(input(sys.argv[0]))

arr= list(range(-1,n))

print(arr)

Answer 1

In Python, range() defaults to counting up by 1. You can change this by providing a negative value for step, which is the third argument to range(). You will also need to provide the correct stop value, which in your case is -n-1.

import stdio
import sys

n = int(input(sys.argv[0]))

arr = list(range(-1,-n-1,-1))

print(arr)

[-1, -2, -3, -4, -5, -6, -7]

Answer 2

Another option is to use a "List Comprehension"

import stdio
import sys

n = int(input(sys.argv[0]+'\nPick a number, any number\n'))

arr= [-i for i in range(1,n+1)]

print(arr)