Yes, it is necessary to use unowned
or weak
to capture self
in this case.
- Your view controller will most likely have a strong reference to the
UITableView
- The table view has strong reference to it's
UITableViewCells
and
- Each cell has strong reference to your
buttonAction
closure.
Using self directly will have as an effect a retain cycle.
This is actually pretty easy to test. Try to present the following view controller and dismiss it:
class TestTableViewCell: UITableViewCell {
var closure: (() -> Void)?
deinit {
print("TestTableViewCell deinit!")
}
}
class TestTableViewController: UITableViewController {
override func viewDidLoad() {
super.viewDidLoad()
tableView.register(TestTableViewCell.self, forCellReuseIdentifier: "TestTableViewCellIdentifier")
}
deinit {
print("TestTableViewController deinit!")
}
override func tableView(_ tableView: UITableView, numberOfRowsInSection section: Int) -> Int {
return 1
}
override func tableView(_ tableView: UITableView, cellForRowAt indexPath: IndexPath) -> UITableViewCell {
let cell = tableView.dequeueReusableCell(withIdentifier: "TestTableViewCellIdentifier", for: indexPath) as! TestTableViewCell
cell.closure = { [weak self] in
guard let self = self else { return }
self.testFunction()
}
return cell
}
func testFunction() {}
}
// Test present
let controller = TestTableViewController()
present(controller, animated: true) {
DispatchQueue.main.asyncAfter(deadline: .now() + 1) {
self.dismiss(animated: true)
}
}
You will have the following output:
TestTableViewController deinit!
TestTableViewCell deinit!
Now presenting the same view controller without weak and you will see that there is no output, meaning that the deinit
functions are not get called and the objects stay in the memory.