Calculating Hits and Misses Percentage in Javascrpt

Asked Sep 24 '20 at 13:05

Active Sep 24 '20 at 13:17

Viewed 92 times

I am making a Whack a Mole like Zombie themed game in Javascript. I wanted to know the accuracy in percentages, like the hits vs missed ratio in percentages. So, i used this code:

let accuracy = (hit / (hit + missed)) * 100

This seems to work and give me the percentages. The only problem is that on the first click instead of showing 100, it shows 10. on rest of the clicks it shows the correct percentages for ex.50,60,75 etc. I have no idea why it shows 10 instaed of 100 on the first click.

edited Sep 24 '20 at 13:17

Mr. Polywhirl

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asked Sep 24 '20 at 13:05

Mir

2

Post the actual code and the (logged) values of `hit` and `miss`. There is the problem, not in that formula. – Samuli Hakoniemi Sep 24 '20 at 13:08
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`1 / (1 + "0") * 100 = 10 ` are you sure you're getting numbers and not strings ? use parseInt(hit) and parseInt(missed) – Sélim Achour Sep 24 '20 at 13:09
ParseInt(hit) and parseInt(missed) has solved the problem. Thank you so much – Mir Sep 24 '20 at 13:17

Calculating Hits and Misses Percentage in Javascrpt

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