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I need to display a view with Courses with its dependable Lectures on an accordion in html. A Course has many Lectures.

class Course(models.Model):
    title = models.CharField(max_length=1500)
    def __str__(self):
        return self.title

class Lecture(models.Model):
    title = models.CharField(max_length=1500)
    course = models.ForeignKey(Course, on_delete=models.CASCADE)
    content = models.TextField()

    def __str__(self):
        return self.title

It seems like all the examples I have found. Get the relationship after doing a filter or getting the first object like this:

Course.objects.first().lecture_set.all()

This gets all the lectures for the first one. But I need to get all Courses with all lectures. Something like this:

Course.objects.all().lecture_set.all() or Course.objects.filter('all').lecture_set.all()

This way I could iterate over Courses and then on each Course iterate again with Course.lectures

Does anyone know the best practice to achieve this?

juanulis3s
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  • you're looking for [prefetch_related](https://docs.djangoproject.com/en/3.1/ref/models/querysets/#prefetch-related) method, the example in docs looks similar to your use-case – yedpodtrzitko Sep 24 '20 at 01:44

1 Answers1

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You can use prefetch_related() In your example it would be like Course.objects.all(). prefetch_related('lecture_set') So after that you can iterate all courses and getting its lectures without accessing database. Make sure that you will access it through object itself like:

{% for course in courses_list %}
     {% for lecture in course.lecture_set.all() %}

There is good library to inspect each request details, like count of database connections per request. So you can optimize your code.

Hope I hepled.

Adam
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