How to get a list with an element removed?

Question

I want to do a job for each item in a list. But I got a problem.
I want this code:

list=[1,2,3]
for i in list:
  func(list.removed(i))

to do this:

func([2,3])
func([1,3])
func([1,2])

How can I make it? Thanks.

That one looked good to me. It includes [this answer](https://stackoverflow.com/a/15738712/3890632) which looks suitable. — khelwood, Sep 23 '20 at 09:40

score 2 · Answer 1 · answered Sep 23 '20 at 09:35

2

Using slices:

for i in range(len(xs)):
    func(xs[:i] + xs[i + 1:])

answered Sep 23 '20 at 09:35

Mateen Ulhaq

score 1 · Answer 2 · answered Sep 23 '20 at 09:41

1

You can use itertools for that, by taking all combinations of the list of its size - 1:

import itertools

lst = [1, 2, 3, 4]
for comb in itertools.combinations(lst, len(lst)-1):
    print(comb)

Gives:

(1, 2, 3)
(1, 2, 4)
(1, 3, 4)
(2, 3, 4)

answered Sep 23 '20 at 09:41

Tomerikoo

2 Answers2