static_cast vs static_cast

Question

I'm new to C++, so please take this lightly. I was using resharper to convert some code from c-style casts to c++ style casts.

This code here:

(unsigned int)(ch - start) <= (unsigned int)(end - start);

Was changed to

static_cast<unsigned>(ch - start) <= static_cast<unsigned>(end - start);

instead of:

static_cast<unsigned int>(ch - start) <= static_cast<unsigned int>(end - start);

Is there ANY difference? And also, is there any peformance differences? This is called billions of times.

There isn't any difference. The two mean the same thing. By convention, the `int` part is often omitted. — Ron, Sep 13 '20 at 18:44
`unsigned int` and `unsigned` by itself mean the same thing. In the `unsigned` by itself case, the `int` is implied. There is no performance difference. — Eljay, Sep 13 '20 at 18:45

score 1 · Accepted Answer · answered Sep 13 '20 at 18:48

1

Is there ANY difference?

unsigned int has 4 more characters than unsigned. There are no other differences.

And also, is there any peformance differences?

No.

answered Sep 13 '20 at 18:48

eerorika

1 Answers1