Why should I use %d for integer in python3?

Asked Sep 09 '20 at 11:18

Active Sep 09 '20 at 11:23

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From experience using %d or %s when formatting an integer in python 2 and 3 gives the same result. On top of that, it seems that using %s instead of %d when formatting an integer is a few nanoseconds faster.

Why should I ever use %d when formatting an integer since it seems to have absolutely no effect on the final result?

In [8]: "foo %s bar" % 1000
Out[8]: 'foo 1000 bar'

In [9]: "foo %d bar" % 1000
Out[9]: 'foo 1000 bar'

asked Sep 09 '20 at 11:18

user1661493

Check https://stackoverflow.com/questions/4288973/whats-the-difference-between-s-and-d-in-python-string-formatting/48660475 – Chris Sep 09 '20 at 11:21
1

You might use `%d` to indicate that the parameter is an integer, and cause an error if it is not one. – khelwood Sep 09 '20 at 11:21
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you can get the same result using print(f"foo {1000} bar") – Sarvesh Pandey Sep 09 '20 at 11:27
Also, see what `"%d"%1.5` does in comparison to `"%s"%1.5` – khelwood Sep 09 '20 at 11:56
Or you can use format – noninertialframe Sep 09 '20 at 12:04

Why should I use %d for integer in python3?

0 Answers0