Python Finding words after and before variable keyword while having commas and spaces in between

Question

My string is

string =  "Amtsgericht Berlin HRB 25665"

How can I find the word before AND after the keyword HRB?

This way I get the word after my keyword:

match = re.compile(r'HRB\s+((?:\w+(?:\s+|$)){1})')
print(match.findall(string))

>>>>> ['25665']

How can I add the keyword (HRB) as a variable into my regex expression?

Please can you show exactly what output you want. – alani Sep 07 '20 at 13:40 — alani, Sep 07 '20 at 13:40

Aviv Yaniv · Accepted Answer · 2020-09-07T14:24:47.730

0

Use (\w+) to match words and format the keyword using f-string:

import re


string =  "Amtsgericht Berlin, HRB 25665"

KEYWORD = 'HRB'

match = re.compile(f'(\w+)[,|\s]*{KEYWORD}[,|\s]*(\w+)')

# [('Berlin', '25665')]
print(match.findall(string))

edited Sep 07 '20 at 14:24

answered Sep 07 '20 at 13:40

Aviv Yaniv

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Thanks you very much. How would you change the regex, if the string would be `` "Amtsgericht Berlin, HRB 25665"``? Very similar, but with a comma in between – PParker Sep 07 '20 at 14:22
1

@PParker Improved answer for you :) – Aviv Yaniv Sep 07 '20 at 14:25
Perfect, thanks a lot. Very helpful for me!!! – PParker Sep 07 '20 at 14:29

Python Finding words after and before variable keyword while having commas and spaces in between

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