I'm working on a problem in which I only want to create a particular rule if a certain Bazel config has been specified (via '--config'). We have been using Bazel since 0.11 and have a bunch of build infrastructure that works around former limitations in Bazel. I am incrementally porting us up to newer versions. One of the features that was missing was compiler transitions, and so we rolled our own using configs and some external scripts.
My first attempt at solving my problem looks like this:
load("@rules_cc//cc:defs.bzl", "cc_library")
# use this with a select to pick targets to include/exclude based on config
# see __build_if_role for an example
def noop_impl(ctx):
pass
noop = rule(
implementation = noop_impl,
attrs = {
"deps": attr.label_list(),
},
)
def __sanitize(config):
if len(config) > 2 and config[:2] == "//":
config = config[2:]
return config.replace(":", "_").replace("/", "_")
def build_if_config(**kwargs):
config = kwargs['config']
kwargs.pop('config')
name = kwargs['name'] + '_' + __sanitize(config)
binary_target_name = kwargs['name']
kwargs['name'] = binary_target_name
cc_library(**kwargs)
noop(
name = name,
deps = select({
config: [ binary_target_name ],
"//conditions:default": [],
})
)
This almost gets me there, but the problem is that if I want to build a library as an output, then it becomes an intermediate dependency, and therefore gets deleted or never built.
For example, if I do this:
build_if_config(
name="some_lib",
srcs=[ "foo.c" ],
config="//:my_config",
)
and then I run
bazel build --config my_config //:some_lib
Then libsome_lib.a
does not make it to bazel-out
, although if I define it using cc_library
, then it does.
Is there a way that I can just create the appropriate rule directly in the macro instead of creating a noop
rule and using a select? Or another mechanism?
Thanks in advance for your help!