Identifying UriBuilder implementation used by Spring WebClient

Question

I use the below syntax to make a get call using get client. In the below example , which implementation of URIBuilder is being used and how is automatically inferenced?

webclient.get().uri(uriBuilder -> uriBuilder.path("/api/person/{personId}")
    .queryParam("param1", aDouble)
    .queryParam("param2", "A string value with spaces")
    .queryParam("param3", aListOfValues)
    .queryParam("param4", null)
    .build(anInteger))

This is the webclient that I am using - WebClient

@CostiCiudatu - I am using https://docs.spring.io/spring/docs/current/javadoc-api/org/springframework/web/reactive/function/client/WebClient.html#builder-- — Punter Vicky, Aug 27 '20 at 22:00
Hmmm... it should be either `UriComponentsBuilder` or `DefaultUriBuilder`. — RichArt, Aug 27 '20 at 22:04

score 1 · Accepted Answer · answered Aug 27 '20 at 22:11

You can decide which implementation is used WebClient by providing a UriBuilderFactory while building it.

The WebClient.Builder has a uriBuilderFactory(UriBuilderFactory) method where you can provide your implementation.

If you don't provide one, it currently uses DefaultUriBuilderFactory which produces UriComponentsBuilder instances.

_{You could always instrument your code to print uriBuilder.getClass() for confirmation.}

Identifying UriBuilder implementation used by Spring WebClient

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