A problem about the code in java especially in skip function

Question

scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

can anyone please explain this code... i'm still confusing about this code and how this code works while compiling

Which part don't you understand, the skip or the regular expression? Btw. for both there is good documentation available. — Henry, Aug 25 '20 at 05:50

score 1 · Answer 1 · edited Dec 18 '20 at 18:40

1

  scanner.skip("(\r\n|[\n\r\u2028\u2029\u0085])?");

You can read all the details of predefined character classes:

Look for horizontal white space and linebreak matcher.

edited Dec 18 '20 at 18:40

answered Aug 25 '20 at 09:25

huntgang99

Nowhere Man · Answer 2 · 2020-08-25T07:15:43.533

0

This code tells scanner to skip unwanted characters in the input ignoring delimiters.

In this case, a set of characters related to new-line handling are skipped:

edited Aug 25 '20 at 07:15

answered Aug 25 '20 at 06:08

Nowhere Man

2

"sets up" scanner might be misunderstood as an ongoing thing. It's not. The code is not "setting up" a condition, it is executing the *skip* right then and there, from the current position of the scanner. – Andreas Aug 25 '20 at 06:17

score 0 · Answer 3 · edited Dec 18 '20 at 18:35

0

Explanation for the string:

\r\n - a pair of CRLFs like in Windows, or any of the following single characters:

\r - CR (carriage return) MacOS line separator,

\n - LF (line feed) Unix line separator,

\u2028 - Unicode line separator,

\u2029 - Unicode paragraph separator,

\u0085 - Unicode next line.

edited Dec 18 '20 at 18:35

Arn

answered Dec 18 '20 at 14:41

bnuracikgoz

3 Answers3