Django can i reverse a parameterized url without passing any arguments?

Question

app_name = 'app_name'
path('url/<uuid:uuid>',someview.as_view(),name='somename')

def get_url():
   return reverse('app_name:somename',args=None)

I want get_url to return 'url/' Is it possible?

If not, can i somehow get the partial url without the param like 'url/'?

No, you can't. The idea is that you should fill in the parameters. It would also be an invalid URL. The slashes in the path are not really "compartments" in the sense that people interpret these as compartments, but it is just a simple slash. — Willem Van Onsem, Aug 24 '20 at 01:13
Both forward and reverse lookup of the URL `url/` would require an additional route. It could lead to the same view if a [default value](https://docs.djangoproject.com/en/3.1/topics/http/urls/#specifying-defaults-for-view-arguments) is defined. — Klaus D., Aug 24 '20 at 01:17

score 2 · Answer 1 · answered Aug 24 '20 at 01:21

2

You can have multiple paths with the same name but with different parameters.

app_name = 'app_name'

urlpatterns = [
    path('url/', someview.as_view(), name='somename'),
    path('url/<str:foo>/', someview.as_view(), name='somename'),
]

When you use reverse the url pattern that matches the name and parameters that you pass will be returned

reverse('app_name:somename', kwargs={'foo': 'bar'})  # /url/bar/
reverse('app_name:somename')  # /url/

answered Aug 24 '20 at 01:21

Iain Shelvington

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Would this be a good practice? Including both urls would enable a user to hit either of these and what if it is an update view? Wouldn't it result in a crash? – Ahsan Aug 24 '20 at 01:26
@Ahsan it makes sense if the view accepts arguments that are not required – Iain Shelvington Aug 24 '20 at 01:32
I always forget to add `app_name` to `reverse` and end up with "Reverse not found". – Amir Shabani Apr 03 '22 at 07:20

score 0 · Answer 2 · answered Mar 09 '22 at 16:48

You could use re_path:

from django.urls import re_path

urlpatterns = [
   re_path('url/(?P<some_id>[0-9]*)$', some_view, name='someview-name'),
]

This way, url/ is valid, url/12 is valid, but url/foobar is not.

Note that when you return reverse('app_name:somename',args=None), None is interpreted as a string, so it's better to do return reverse('app_name:somename',args=''). Anyway, re_path('url/(?P<some_id>[0-9]*|None)$' also works.

Django can i reverse a parameterized url without passing any arguments?

2 Answers2