Handle api response using sealed class in rxjava

Question

I want to handle api response using sealed class

sealed class Result<out T> {

    data class Success<out T>(val value: T) : Result<T>()
    data class Failure<out T>(val throwable: Throwable) : Result<T>()
}

My api is working properly for

@POST("/api/doctor_app/UpdateProfile")
fun UpdateProfile(@Body request: Doctor): Single<GenericResponse>

and when I updated my api to

@POST("/api/doctor_app/UpdateProfile")
fun UpdateProfile(@Body request: Doctor): Single<Result<GenericResponse>>

Failed to invoke private com.utils.Result() with no args

How can I achieve response like

configService.UpdateProfile(doctor)
            .subscribeOnIO()
            .map {
                when(it){
                    is Result.Success -> Result.Success(it.value)
                    is Result.Failure -> Result.Failure<GenericResponse>(it.throwable)
                }
            }

where subscribeOnIO

fun <T> Single<T>.subscribeOnIO(): Single<T> {
    return this.subscribeOn(Schedulers.io())
        .observeOn(AndroidSchedulers.mainThread())
}

Have you solved it? I am facing the same issue – Omar Hassan Oct 03 '21 at 12:00 — Omar Hassan, Oct 03 '21 at 12:00

score 0 · Answer 1 · answered Aug 28 '20 at 07:34

0

did you try something like this:

@POST("/api/doctor_app/UpdateProfile")
fun UpdateProfile(@Body request: Doctor): Single<Result.Success<GenericResponse>>

and then

configService.UpdateProfile(doctor)
        .onErrorReturn { Result.Failure(it) }
        .subscribeOnIO()
        .map {
            when(it){
                is Result.Success -> Result.Success(it.value)
                is Result.Failure -> Result.Failure<GenericResponse>(it.throwable)
            }
        }

answered Aug 28 '20 at 07:34

borichellow

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why you are returing Result.Success in UpdateProfie – Zar E Ahmer Aug 28 '20 at 07:37
it's like "Expected result". and if there is an error you map it into `Result.Failure` – borichellow Aug 28 '20 at 07:43
I am talking about Single> – Zar E Ahmer Aug 28 '20 at 07:48
yeah, i got. `Single>` is your expected result. Something you'd like to get from the request. And if there is any error you map it into `Result.Failure` – borichellow Aug 28 '20 at 08:20
@borichellow I have followed the same approach but i am always getting this exception, java.lang.RuntimeException: Failed to invoke private Result() with no args – Omar Hassan Oct 03 '21 at 11:58
@OmarHassan my approach isn't correct. Result should be handle at repository level. Read Uncle Bob Clean architecture – Zar E Ahmer Oct 07 '21 at 10:25

Handle api response using sealed class in rxjava

1 Answers1