Shell script does not recognize alias

Question

I have a file named run. These are the contents:

#!/bin/zsh

python

To make the file executable, I ran chmod a+x run. I typed in ./run into the terminal. It activates the Python 2.7 shell. The reason this is unexpected is because in my .zshrc file I have an alias: alias python="python3". Why does zsh not recognize my alias?

This is for bash, not zsh, but should help you understand the issue: https://askubuntu.com/questions/98782/how-to-run-an-alias-in-a-shell-script — jdaz, Aug 16 '20 at 01:23
@Hedy That is in my `.zshrc` file which is located at `~/.zshrc`. `run` is located at `~/Documents/PythonGame/run` — shreyasm-dev, Aug 16 '20 at 01:35
I know that, I just thought that putting the alias into the script (as well as in zshrc if you like) then run `python` might work — hedy, Aug 16 '20 at 01:36

score 4 · Accepted Answer · answered Aug 17 '20 at 09:01

4

You need to enable alias processing. Do in your script a

setopt aliases

before defining your alias.

answered Aug 17 '20 at 09:01

user1934428

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It doesn't work? I tried putting it in both `run` **and** `~/.zshrc` and even restarted the shell, but it still doesn't work. The only thing that has worked so far is putting the alias in `run` as @Hedy suggested. – shreyasm-dev Aug 17 '20 at 11:52
@GalaxyCat105 : `.zshrc` doesn't matter in this context. It is not processed by your script anyway. **Inside** `run`, you have to do `setopt aliases; alias python="python3"`, as I explained in my answer (_do it **in** your script, **before** defining your alias_) – user1934428 Aug 17 '20 at 12:55

Shell script does not recognize alias

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