this is the continue question from find out time difference for every user in condition mysql 5.7
this is my fiddle https://dbfiddle.uk/?rdbms=mysql_5.7&fiddle=31b3be9d1e2444eb0b32c262176aa4b4
i have this table
CREATE TABLE test (
ID INT,
user_id INT,
createdAt DATE,
status_id INT
);
INSERT INTO test VALUES
(1, 13, '2020-01-01', 8),
(2, 13, '2020-01-03', 8),
(3, 13, '2020-01-06', 8),
(4, 13, '2020-01-02', 7),
(5, 13, '2020-01-03', 7),
(6, 14, '2020-03-03', 8),
(7, 13, '2020-03-04', 4),
(8, 15, '2020-04-04', 7),
(9, 14, '2020-03-02', 6),
(10, 14, '2020-03-10', 5),
(11, 13, '2020-04-10', 8);
select * from test where status_id != 7
order by createdAt;
+----+---------+------------+-----------+
| ID | user_id | createdAt | status_id |
+----+---------+------------+-----------+
| 1 | 13 | 2020-01-01 | 8 |
| 2 | 13 | 2020-01-03 | 8 |
| 3 | 13 | 2020-01-06 | 8 |
| 9 | 14 | 2020-03-02 | 6 |
| 6 | 14 | 2020-03-03 | 8 |
| 7 | 13 | 2020-03-04 | 4 |
| 10 | 14 | 2020-03-10 | 5 |
+----+---------+------------+-----------+
the id is the id of the transaction, user_Id is the id of the users who doing the transaction, createdAt are the date transaction happen, status_id is the status for the transaction (if the status_Id is 7, then the transaction are denied or not approval).
so on this case, I want to find out time difference for every approval transaction on every repeat users on time range between '2020-02-01' until '2020-04-01', repeat users are the users who doing transaction before the end of the time range, and at least doing 1 transaction again in the time range, on this case, users are doing approval transaction before '2020-04-01' and at least doing 1 more approval transaction again in between '2020-02-01' and '2020-04-01'.
for that problem i used this query based on answers from @Akina
-- Get pairs (current transaction, previous transaction) for these users
SELECT t1.user_id,
t1.createdAt,
t2.createdAt,
DATEDIFF(t2.createdAt, t1.createdAt) diff
-- table for a transaction
FROM test t1
-- table for prev. transaction
JOIN test t2 ON t1.user_id = t2.user_id
AND t1.createdAt < t2.createdAt
AND 7 NOT IN (t1.status_id, t2.status_id)
-- get data only for users from prev. query
JOIN (SELECT t3.user_id
FROM test t3
WHERE t3.status_id != 7
GROUP BY t3.user_id
HAVING SUM(t3.createdAt < '2020-04-01') > 1
AND SUM(t3.createdAt BETWEEN '2020-02-01' AND '2020-04-01')) t4 ON t1.user_id = t4.user_id
-- check that there is no approved transaction between selected transactions
WHERE NOT EXISTS (SELECT NULL
FROM test t5
WHERE t1.user_id = t5.user_id
AND t5.status_id != 7
AND t1.createdAt < t5.createdAt
AND t5.createdAt < t2.createdAt)
the output table was like this
+----------+------------+------------+------+
| user_id | createdAt | createdAt | diff |
+----------+------------+------------+------+
| 13 | 2020-01-01 | 2020-01-03 | 2 |
| 13 | 2020-01-03 | 2020-01-06 | 3 |
| 14 | 2020-03-02 | 2020-03-03 | 1 |
| 13 | 2020-01-06 | 2020-03-04 | 58 |
| 14 | 2020-03-03 | 2020-03-10 | 7 |
+----------+------------+------------+------+
the problem is, this query count time difference in time range ('2020-02-01' until '2020-04-01') for each users, and count time difference also before the time range (see users_id 13, that users also counting time difference in date '2020-01-01' until '2020-01-03'). what i want is, if the users had a transaction before time range, i want counting only his users_id last transaction before time range (on this case, users_id 13 who i want to counting just only time difference in '2020-01-06' until '2020-03-04' because in 06 january 2020 is the date when the users last transaction before time range. so on that case, the expected results was like this :
+---------+------------+------------+------+
| user_id | createdAt | createdAt | diff |
+---------+------------+------------+------+
| 14 | 2020-03-02 | 2020-03-03 | 1 |
| 13 | 2020-01-06 | 2020-03-04 | 58 |
| 14 | 2020-03-03 | 2020-03-10 | 7 |
+---------+------------+------------+------+