Concurrent futures - Extracting file name along with the output

Asked Aug 10 '20 at 13:57

Active Aug 10 '20 at 13:57

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I have a folder of 100 images on which I am expected to perform some extraction task... in order to save time, I wanted to use concurrent.futures and it worked well.. the problem now is I am not able to map the output to the images in the folder.. (I do not know which extraction belongs to which file).. my code looks something like this:

def main():
    with concurrent.futures.ProcessPoolExecutor() as executor:
        y=([val for val in executor.map(extract_features_new, img_list)])
    return y    
       
if __name__ == '__main__':
    x=main()

is there an option for me to append the file name when it is returning the output??? Can someone help?

asked Aug 10 '20 at 13:57

Moses Gunaseelan

`executor.map` should return with the same order as the arguments `img_list` provided – M Z Aug 10 '20 at 14:05
is that true? what if one image is smaller and processed faster than the previous image in queue... in that case, the result order will be changed.. right?? – Moses Gunaseelan Aug 10 '20 at 14:25
I'm pretty certain – but if you don't want to risk it, just have the function also return the filename as part of a tuple – M Z Aug 10 '20 at 14:33
Yes, that must be an easy way... – Moses Gunaseelan Aug 10 '20 at 15:23
This [answer](https://stackoverflow.com/a/63362019/5722359) may help you? – Sun Bear Aug 12 '20 at 17:28

Concurrent futures - Extracting file name along with the output

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