How do i declare multiple items in a for loop in python

Question

alright, So I'm working on a small python Command-line calculator,

this was just a test:

import time

calc = print("\n what calculation do you want to use\n")

time.sleep(1)

menu = print(" MENU:\n **********\n mult for multiplication\n add for addition\n sub for substraction\n div for divide\n **********")

time.sleep(1)

ask = input(" what calculation do you want to use from the menu? \n")

much = input(" how many numbers do you calculate? (5 maximumn & 2 minimum) \n")

if(much == " 2" or much == "2" and ask == " mult" or ask == "mult"):
    num1_2 = input(" First Number? ")
    num2_2 = input("\n Second Number? ")
    answer_2 = print(int(num1_2) * int(num2_2))


time.sleep(11)

and it was working correctly, i was planning to complete all the if: and the elif: statements, but then i thought that i could make my code more efficient, so i thought i can use a for loop like this:

for value in range(int(much)):
    output = input("Number? ")

print(int(value) * int(value))

note: (much) is the the variable name that i used for declaring how many numbers does the user wants to calculate

so, when i used the for loop it showed a wrong answer, for example when i multiplied 2 by 2 the answer was 1.

so how can i declare multiple items in the for loop to multiplie the first user input by the second one?

this is confusing because the number of outputs is not stable.

You have it printing *value x value*, where *value* is the last index (if much is 2, then value is 1), not the number the user input. — Joe, Aug 03 '20 at 22:54
I would try output = 1 before the for loop, and output *= input(“Number”) inside the loop. Then print output. — Joe, Aug 03 '20 at 22:58
i tried but when i run the program and i type 2 times 2 the program closes and does not print anything — Dev Turaani, Aug 03 '20 at 23:05
I should have written output *= int(input(“Number”)), since input returns a string. The answer by @redmicelles below works, right? — Joe, Aug 03 '20 at 23:18
yes thank you, and yes The answer by @redmicelles`is`working. — Dev Turaani, Aug 04 '20 at 00:11

score 0 · Accepted Answer · answered Aug 03 '20 at 23:04

0

Do know that, the for loop remembers only the value of the last iteration. You may have a variable(Not necessarily a list) outside of store the values of your iteration result. For example:

result = 1
for value in range(int(much)):
    output = input("Number? ")
    result*=int(output)
print(result)

answered Aug 03 '20 at 23:04

Seyi Daniel

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Yes that worked but i didn't quite understand what do you mean by (You may have a variable(Not necessarily a list) outside of store the values of your iteration result)? – Dev Turaani Aug 04 '20 at 00:10
I think @redmicelles was saying that you can use an int or float (such as *result* in the example given), instead of a list as suggested by alaniwi, to store the intermediate and final computations. – Joe Aug 04 '20 at 04:10

How do i declare multiple items in a for loop in python

1 Answers1