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In the included screenshot, I am trying to derive the simplest boolean function. I used these four groups of ones to derive the different variable groups. According to the solution in my book, I don't have the correct four groups, but it does seem to be a grouping of four and not five. Does anyone see a grouping scenario I might have missed? I tried wrapping around but that doesn't seem to help either.

enter image description here

My final function of w, x, y, z was the following and it is apparently not the solution:

F (w, x, y, z) = w'x'z + w'yz' + xy' + wz

karnaugh map with my grouping of 1s

Axel Kemper
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FullStackJunkie
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1 Answers1

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My solution is

F(w, x, y, z) = x y'  + w z + x' z + w' y z'

Your term w'x'z can be slimmed down (or merged) to x'z as a disjunction of w'x'z and wx'z.

Axel Kemper
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  • Thank you @Axel Kemper. When I looked up disjunction, I wasn't a hundred percent sure if I got it. If I were to put it in my own terms, could I say that we can merge w'x'z to wx'z and in this scenario that w and w' cancel each other out? Actually that doesn't make sense. Let me see if I can do some research on this term "disjunction." – FullStackJunkie Aug 04 '20 at 13:54
  • Replace disjunction by logical or. – Axel Kemper Aug 04 '20 at 15:02
  • I actually ended up finding this afterwards! But still, thank you for that clarification! – FullStackJunkie Aug 06 '20 at 06:41