Python reflection, getter to methods

Question

class A:
    def __init__(self):
        self.var = 10
    def print(self):
        print("hiiiiii")

For an object of A, we can easily access the attributes with getattr and setattr. Is there any way in Python to have an instance of class and a method name and call it indirectly, like:

MagicalMethod( A(), "print" )

then prints "hiiiiii" for me.

`getattr(A(), "print")()`? Methods are just callable attributes. — jonrsharpe, Aug 03 '20 at 12:51
yup it means by passing an instance of class like A() and the method name it calls the method for A() — Jamal Musiala, Aug 03 '20 at 12:51
however what you say doesn't work but throw no exception either — Jamal Musiala, Aug 03 '20 at 12:53

score 0 · Answer 1 · answered Aug 03 '20 at 12:52

0

That would be getattr:

>>> getattr(A(), 'print')()
hiiiiii

(Note that you still have to call the return value of getattr; you can define a wrapper to do that for you:

def MagicalMethod(obj, name, *args, **kwargs):
    return getattr(obj, name)(*args, **kwargs)

)

operator.methodcaller provides a slightly different kind of indirection.

>>> from operator import methodcaller
>>> f = methodcaller('print')
>>> f(A())
hiiiiii

answered Aug 03 '20 at 12:52

chepner

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thank you so much, for the getattr I was not putting the brackets so it wasn't working, thank you again :) – Jamal Musiala Aug 03 '20 at 12:57

Python reflection, getter to methods

1 Answers1