In the below example I want to find whether the sentence starts with 'ap' and ends with 'e'.
example: a="apple"
if [[ "$a" == ^"ap"+$ ]]
This is not giving proper output.
In the below example I want to find whether the sentence starts with 'ap' and ends with 'e'.
example: a="apple"
if [[ "$a" == ^"ap"+$ ]]
This is not giving proper output.
You don't mention which shell you're using, but the [[
in your attempt suggests you're using one that expands upon the base POSIX sh language. The following works with at least bash
, zsh
and ksh93
:
$ a=apple
$ [[ $a == ap*e ]] && echo matches # Wildcard pattern
matches
$ [[ $a =~ ^ap.*e$ ]] && echo matches # Regular expression - note the =~
matches