How to call class by its name dynamically in Kotlin

Question

Assume I have a fragment called "LoginFragment". I want to use this fragment in add transaction below:

fTransaction.add(R.id.login_fragment, LoginFragment())

But I need call it by name dynamically like this:

val name = "LoginFragment"
fTransaction.add(R.id.login_fragment, name())

How should I do this? Thank you

Kotlin is statically-typed language, you can't do dynamic typing here, the Types are resolved at compile-time. — Animesh Sahu, Jul 27 '20 at 05:15
You could however make a checking function `operator fun String.invoke(): Fragment { if(this == "LoginFragment") return LoginFragment() else throw IllegalArgumentException("Message") }` or you could chain them using a `when` instead of `if`. — Animesh Sahu, Jul 27 '20 at 05:18

score 1 · Accepted Answer · answered Jul 27 '20 at 06:58

If you want to instantiate a Fragment by it's name you can use FragmentFactory to instantiate the Fragment:

try {
    val fragmentName = "LoginFragment"
    val fragmentFullName = "your.package.name.$fragmentName"
    val fragment = supportFragmentManager.fragmentFactory.instantiate(classLoader, fragmentFullName)
    supportFragmentManager
            .beginTransaction()
            .add(R.id.login_fragment, fragment)
            .commitNow()
} catch (e: java.lang.Exception) {
    e.printStackTrace()
}

How to call class by its name dynamically in Kotlin

1 Answers1