How to pass multiple files as a input to an api using Rest Assured

Question

In this method below I was making an API call to a locally running API that accepts only one file as a request, but is there any possible way to make an API call that accepts multiple files as request using Rest Assured dynamically at run time based on requests for that API? like how to add multiple files as an API request in Rest Assured at run time dynamically?

    public String restTest() {
        String resp = RestAssured.given().multiPart("file", new File("C:/Local/file/path/LocalFiles/file.txt")).when().post("http://localhost:4444/local/upload").then().assertThat().statusCode(200).and().extract().body().asString();

    return resp.toString();
        
    }

score 2 · Accepted Answer · edited Jul 23 '20 at 13:58

public static void main(String[] args) throws MalformedURLException {

        Response response;
        RequestSpecification request = RestAssured.given().header("content-type", "multipart/form-data");
        for (int i = 1; i <= 2; i++) {
            request.multiPart("file", new File("D:/testtemplates98_" + i + "Data.xlsx"));// File parameters will be
                                                                                            // dynamic
        }
        response = request.post(new URL("https://jquery-file-upload.appspot.com/"));
        System.out.println(response.getBody().asString());
}

It is working perfectly . Thank you so much for providing logic — Sai, Aug 26 '20 at 13:04

score 0 · Answer 2 · answered Jul 20 '20 at 13:15

0

rest assured uses a builder pattern so you can just stack the files like

given().
         multiPart("file1", new File("/home/johan/some_large_file.bin")).
         multiPart("file2", new File("/home/johan/some_other_large_file.bin")).
         multiPart("file3", "file_name.bin", inputStream).
         formParam("name", "value").
expect().
         body("fileUploadResult", is("OK")).
when().
         post("/advancedFileUpload");

and so you can send multiple files.

answered Jul 20 '20 at 13:15

Tobsch

175
2
10

thanks for quick replay @[https://stackoverflow.com/users/5168458/tobsch] , like how can i do the same dynamically? – Pradeep maiya Jul 20 '20 at 13:38
define a variable for given() e.g. and add dynamically the multiParts – Tobsch Jul 22 '20 at 10:50

score 0 · Answer 3 · answered Mar 21 '21 at 13:45

File files[] = getFileList();
RequestSpecification request = RestAssured.given().contentType(ContentType.MULTIPART_FORM_DATA.toString()).request();
for (File file: files) {
  request.multiPart("files", new File(file.getAbsolutePath()));
}
request.post().then().statusCode(200);

How to pass multiple files as a input to an api using Rest Assured

3 Answers3

Linked

Related