Using sinon how to avoid testing nested function?

Question

I'm using mocha/chai/sino and I'm new with the three of them.

const a = () => {
  b();
}

const b = () => {
  console.log('here');
}

In this example I just want to test that b is been called when calling a without executing b.

Something like:

it('test', () => {
  const spy = sinon.spy(b);
  a();
  chai.expect(spy.calledOnce).to.be.true;
})

score 2 · Accepted Answer · answered Jul 17 '20 at 13:09

Sinon's stub is what you are looking for.

Sinon Stubs

When to use stubs? Use a stub when you want to:

Control a method’s behavior from a test to force the code down a specific path. Examples > include forcing a method to throw an error in order to test error handling.

When you want to prevent a specific method from being called directly (possibly because it triggers undesired behavior, such as a XMLHttpRequest or similar).

it('test', () => {
  const stub = sinon.stub(b);
  a();
  chai.expect(stub.calledOnce).to.be.true;
})

Using sinon how to avoid testing nested function?

1 Answers1