How to join multiple mp3 files?

Question

Reading other questions I was wondering how to join multiple mp3 files like this. I tried this code but I'm getting as an output just the 2 latest mp3 files in the output.mp3... The expected output should be all the files into 1 mp3 file.

from pydub import AudioSegment
from os import getcwd
import glob

cwd = (getcwd()).replace(chr(92), '/')
export_path = f'{cwd}/result.mp3'

MP3_FILES = glob.glob(pathname=f'{cwd}/*.mp3', recursive=True)
silence = AudioSegment.silent(duration=15000)
count, lenght = 0, len(MP3_FILES)

for n, mp3_file in enumerate(MP3_FILES):
    mp3_file = mp3_file.replace(chr(92), '/')
    print(n, mp3_file)

    count += 1
    if count == 1:
        # We get here upon fetching the first audio file from the list.
        # So we load it into `audio1`
        audio1 = AudioSegment.from_mp3(mp3_file)
        print('audio1')

    elif count == 2:
        # We get here upon fetching the second audio file from the list.
        # So we load it into `audio2`
        audio2 = AudioSegment.from_mp3(mp3_file)
        print('audio2')

    elif count == 3:
        # We get here upon fetching the THIRD audio file from the list.
        # Instead of loading it, we SET `res` to the sum of `audio1+silence+audio2`
        # We don't do anything with the third file, in fact we skip it
        #
        res = (audio1 + silence + audio2)
        print('Merging')

        # Here we reset `count`, so we basically start over the same cycle:
        #  - read the NEXT two audio files, skip the third, and REPLACE `res` to the NEW sum
        #    of the current `audio1`/`audio2` files
        count = 0

    if (n + 1) == lenght:
        res.export(export_path, format='mp3')
        print('\ndone!')

sal · Accepted Answer · 2020-07-16T06:05:51.343

From what I can see, there is an issue with looping. I am commenting below the original code (just the for loop though) to give some insights:

for n, mp3_file in enumerate(MP3_FILES):
    mp3_file = mp3_file.replace(chr(92), '/')
    print(n, mp3_file)

    count += 1
    if count == 1:
        # We get here upon fetching the first audio file from the list.
        # So we load it into `audio1`
        audio1 = AudioSegment.from_mp3(mp3_file)
        print('audio1')

    elif count == 2:
        # We get here upon fetching the second audio file from the list.
        # So we load it into `audio2`
        audio2 = AudioSegment.from_mp3(mp3_file)
        print('audio2')

    elif count == 3:
        # We get here upon fetching the THIRD audio file from the list.
        # Instead of loading it, we SET `res` to the sum of `audio1+silence+audio2`
        # We don't do anything with the third file, in fact we skip it
        #
        res = (audio1 + silence + audio2)
        print('Merging')

        # Here we reset `count`, so we basically start over the same cycle:
        #  - read the NEXT two audio files, skip the third, and REPLACE `res` to the NEW sum
        #    of the current `audio1`/`audio2` files
        count = 0

    if (n + 1) == lenght:
        res.export(export_path, format='mp3')
        print('\ndone!')

If you want - as you mention - just concatenate all the files into a single audio, with silence in between, you shouldn't need to check the count, nor enumerate. I will keep enumerate because it can print nicely to show a bit more context. So, here's my take:

from pydub import AudioSegment
from os import getcwd
import glob

cwd = (getcwd()).replace(chr(92), '/')
export_path = f'{cwd}/result.mp3'

MP3_FILES = glob.glob(pathname=f'{cwd}/*.mp3', recursive=True)

silence = AudioSegment.silent(duration=15000)
full_audio = AudioSegment.empty()    # this will accumulate the entire mp3 audios

for n, mp3_file in enumerate(MP3_FILES):
    mp3_file = mp3_file.replace(chr(92), '/')
    print(n, mp3_file)

    # Load the current mp3 into `audio_segment`
    audio_segment = AudioSegment.from_mp3(mp3_file)

    # Just accumulate the new `audio_segment` + `silence`
    full_audio += audio_segment + silence
    print('Merging ', n)

# The loop will exit once all files in the list have been used
# Then export    
full_audio.export(export_path, format='mp3')
print('\ndone!')

thank you for you complete answer! but this is giving me an error: `Gains must be the second addend after the " TypeError: Gains must be the second addend after the AudioSegment` what can I do? — , Jul 16 '20 at 05:55
I solve it using `full_audio = AudioSegment.empty()` before the for loop, instead of `full_audio = None` — , Jul 16 '20 at 06:03

How to join multiple mp3 files?

1 Answers1