js - shallow copy object, preserve prototype, but don't run constructor

Question

How do you copy an object, preserving its prototype, without running the constructor?

Everything below is context if you're wondering why I want to do such a thing, feel free to ignore it and answer the question.

I'm just experimenting with bringing RAII/ownership concepts into javascript (for fun and curiosity). Surprisingly, I have a solution for destructors that works quite well, but I'm actually stumbling on copy constructors and move constructors.

Specifically, I have a class FileIO:

class FileIO {
    constructor(filename) {
        this.connection = new FileConnection(filename);
    }

    destructor() {
        this.connection.close();
    }

    move() {
        const copy = _how_do_I_(); //copy of this, without running constructor().
        copy instanceof FileIO; // should be true
        // move connection to copy
        copy.connection = this.connection;
        this.connection = null;
        return copy;
    }

    write() {/* TODO */}
    read() {/* TODO */}

}

Ideally, I would be able to do this:

function main() {
    const fileIO = new FileIO("./something.txt");
    useTheFile(fileIO.move());
}

You can see, I don't want to do copy = {...this} because it won't be an instance of FileIO anymore. Also, I can't do copy = new this.constructor(...) because I don't want to duplicate the file connection. Is this even possible?

Thank you.