Python - concatenate root directory name with all sub-folder names

Question

I have a root folder "topfolder". Inside that folder, I have multiple subfolders, "a", "b", "c". I want to rename these subfolders so that they are concatenated with the root folder, such that they become "topfolder_a", "topfolder_b" and so on. Is this relatively easy to do with Python? I think I am almost there with this code but I can't get the last part.

test_directory = "./topfolder"
for child in os.listdir(test_directory):
    test_path = os.path.join(test_directory, child)
    if os.path.isdir(test_path):
        print(test_path)

score 1 · Accepted Answer · edited Jul 02 '20 at 20:50

1

Try os.rename:

import os

test_directory = "./topfolder"
for child in os.listdir(test_directory):
    test_path = os.path.join(test_directory, child)
    rename_path = os.path.join(test_directory, test_directory + "_" + child)
    if os.path.isdir(test_path):
        print(test_path, rename_path)
        os.rename(test_path, rename_path)

edited Jul 02 '20 at 20:50

warsong

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answered Jul 02 '20 at 19:33

Hao Li

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7u5h4r · Answer 2 · 2020-07-02T19:48:19.737

For changing dir name check this change folder names. It's using os.rename

For the parent name, you can use split.

path = os.path.dirname(CURRENT_DIR)
path.split('/')[-1]

CURRENT_DIR is your current working dir in your case it's child is suppose.

Now you have a child and parent name both. You can figure concatenate them and rename them from the reference above.

Well, that's a long solution. but it explains how it'll work. but rename takes full path so you can directly pass the path to rename

os.rename(CURRENT_DIR, test_directory + SEPERATOR + child)

here your SEPERATOR is '-' and you have the child in the loop

score 0 · Answer 3 · answered Jul 02 '20 at 19:29

import os
import shutil

test_directory = "./topfolder"
for child in os.listdir(test_directory):
    test_path = os.path.join(test_directory, child)
    if os.path.isdir(test_path):
      shutil.move(test_path, os.path.join(test_directory, f"{test_directory}_{child}"))

In case you want to retain the orginal forder you can replace move with below

shutil.copytree(test_path, os.path.join(test_directory, f"{test_directory}_{child}"))

Python - concatenate root directory name with all sub-folder names

3 Answers3