A brief explanation about my app:
the application in which I'm working on is such a greeting cards designer. Imagine something in which there is a background image, and an indefinite number of "layers" (in particular, pictures) that stay over the background and can be moved, resized, moved front and back, etc...
It is also possibile to apply particular shapes to these layers, like a star, an ellipse, .. and after the card is made, it's possibile to save is to jpeg file.
The problem
Everything works correctly, but I detected that when a shape is applied to a layer, a memory leak is generated.
Here is the code of the UserControl of each layer:
<UserControl>
.....
<Grid x:Name="_myGrid" >
<Border x:Name="im_the_problem" BorderThickness="0" OpacityMask="{Binding Path=MyMask.Data, Converter={StaticResource MaskConverter}}">
<!-- My Image... -->
</Border>
</Grid>
</UserControl>
where MaskConverter code is the following:
public class MaskConverter : IValueConverter
{
public object Convert(object value, Type targetType, object parameter,
System.Globalization.CultureInfo culture)
{
String maskData = value as String;
if (maskData == null)
return null;
if (maskData == "")
return null;
VisualBrush vb = new VisualBrush();
vb.Visual = XamlReader.Parse(maskData) as Visual;
return vb;
}
public object ConvertBack(object value, Type targetType, object parameter,
System.Globalization.CultureInfo culture)
{
throw new NotSupportedException();
}
}
The Parameter "MyMask.Data" is a XAML Path (that is the shape that I'm applying) that I dinamically load from a textfile that contains different shapes.
So, the principle is that if I have the border named *im_the_problem*, the memory is NOT released. If I comment *im_the_problem* (so I'll just have rectangular layers/pictures without shapes) everything work like a charm, without memory leaks.
The problem should be in the OpacityMask + VisualBrush.
Am I doing something wrong? Or is there a known problem? Is there a way to do the same (apply a shape to a picture..) in a different manner?
Thanks.