This regex is supposed to capture what's after the = sign and what's before the ).
Why does it return both the = and ) in the output. Is this how it works? Or am I doing something wrong?
const s = '=foo)';
console.log(s.match(/=(.*)\)/g))
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If you don't need to match multiple instances and you want to get what's in the capturing group then you get get rid of the g flag and retrieve solely the capturing group:
const s = '=foo)';
console.log(s.match(/=(.*)\)/)[1]);
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And if there are multiple instances? – Norman Jun 30 '20 at 18:28
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And if multiple matches are needed, you can use [`exec`](https://stackoverflow.com/a/19913702/1913729) instead – blex Jun 30 '20 at 18:29