Program to print the first 10 perfect squares

Question

I am trying to go over the natural number and test each natural number if it is the perfect square print that number, but my only condition is that print only first 10 perfect square numbers.

i =2
n=1 #used for counting

while 10>=n:
        for j in range(1,i):
            x =1
            while x*x<=j:
                if x*x==j:
                    print(j)
                    n+=1
                x+=1
            i+=1
            j+=1

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Is there a reason you are trying to do it this way rather than just printing the squares of the first ten integers? — Mark, Jun 29 '20 at 15:23
@MarkMeyer Because a [perfect square](https://en.wikipedia.org/wiki/Perfect_square) is something different. — Matthias, Jun 29 '20 at 16:15
It seem that the intention of your code is to go over the natural numbers j and test each if it is a square. The test of being a square you are doing by squaring and checking if equal to j. One mistake in your code is that each time the outer `while` enters, the `j` will restart from 1 in the `for j in range(1,i)`. You can get rid of that `for`. There is already a j+=1 incrementing the `j`. — NotDijkstra, Jun 29 '20 at 16:20
@Matthias that still seems the same to me. Can you tell me the first ten perfect squares then? — Mark, Jun 29 '20 at 16:26
@MarkMeyer I think they are half-joking, implying that a program checking the definition would do what Raj tried to do: check each integer to see if they satisfy the definition. Namely, that there exist an integer, which square is the number. — NotDijkstra, Jun 29 '20 at 16:28
@NotDijkstra -- maybe so, tone is hard to interpret in text. — Mark, Jun 29 '20 at 17:20
@MarkMeyer Somehow that was an `OutOfCoffeeError` on my side. Indeed it's as simple as `print(', '.join(map(str, (i**2 for i in range(1, 11)))))`. — Matthias, Jun 29 '20 at 20:00
@NotDijkstra you are correct I am trying to go over the natural number and test each natural number if it is perfect square print that number, but my only condition is that print only first 10 perfect square number. — Raj, Jun 30 '20 at 10:18

score 0 · Answer 1 · answered Jun 29 '20 at 16:17

Perfect squares are just:

1 * 1 = 1
2 * 2 = 4
3 * 3 = 9
4 * 4 = 16
...

So you can just make a loop that goes from 1 to any int number you want (in your example it's 10), and print the square of this number like so:

for i in range(1, 11):    # it's 11 because it ranges to 11 - 1, so 10
    print(i*i)

Output:

Program to print the first 10 perfect squares

1 Answers1