Generating Rust executable or library, depending on the target platform

Question

I am targeting my Rust project for Windows and Linux.

On Windows, the code needs to be linked to an executable, whereas on Linux - as a shared library.

To link the project as a Linux shared library, I added the following section to Cargo.toml:

[lib]
name = "my_project_name"
crate-type = ["cdylib"]

However that results in shared library generated on Windows, too.

Is there a way to tell Rust compiler to link the project as executable on Windows and as a library on Linux?

I think it not possible, but you may try to build the binary and the library for both platforms, then using the required ones — Kitsu, Jun 29 '20 at 14:34

score 1 · Accepted Answer · answered Jun 29 '20 at 14:38

1

As far as I can see it's not possible to do so right now. Closest information I could find was this for a similar use case.

answered Jun 29 '20 at 14:38

ShadowMitia

1 Answers1