Return items from array with index 1 to 5 Javascript

Question

How can i console.log items from index 1 to 5 in current array? Using Loop

let cars = ["AUDI","BMW","LEXUS","VOLKSWAGEN","FERRARY","PORSCHE"]

const mappedCars=cars.map((item, i) => {
    console.log("The current index is: " + i);
    console.log("The current element is: " + item);
    console.log("\n");
    return item; //equivalent to list[index]
});

console.log(mappedCars);

If you must use a loop, you'll need to create an empty array, loop over the indexes you want and push the entries in to the new array — Phil, Jun 29 '20 at 01:34
I tried to do it but my brain is over exhausted,sorry for bothering you more but can you give me simple example? — Roffy bc, Jun 29 '20 at 01:35
What happens if the array is shorter than 5? What happens if it's shorter than 1? What should the result be for these edge-cases? — Phil, Jun 29 '20 at 01:35
The task is just to loop over an existing array and console.log item from index 1 to 5 , that cases does not exist in task — Roffy bc, Jun 29 '20 at 01:36
Also array is given in task already,It s not created manually — Roffy bc, Jun 29 '20 at 01:37
Your question says _"How can i **return** items..."_ which is quite different to just `console.log()`. You should always be thinking of boundary conditions for your code. Please [edit your question](https://stackoverflow.com/posts/62629856/edit) to describe **exactly** what you're trying to do and what should happen in unfavourable conditions — Phil, Jun 29 '20 at 01:40
`for(var i=1; i<=Math.min(5, cars.length-1); i++) console.log("Index="+i+" Value="+cars[i]);` If there are less than two cars, no output. if there are less than 6 cars, output will be less than 5 cars. — iAmOren, Jun 29 '20 at 02:06

score 3 · Answer 1 · answered Jun 29 '20 at 01:45

3

With a for loop:

let cars = ["AUDI","BMW","LEXUS","VOLKSWAGEN","FERRARY","PORSCHE"]

for(i = 1; i<cars.length; i++){
    console.log("The current index is: " + i);
    console.log("The current element is: " + cars[i]);
    console.log("\n");
};

answered Jun 29 '20 at 01:45

sonEtLumiere

4,461
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score 3 · Answer 2 · answered Jun 29 '20 at 02:25

With for loop you can define the initial condition as well as loop terminating condition.

for ([initialExpression]; [condition]; [incrementExpression])
 statement

let cars = ["AUDI","BMW","LEXUS","VOLKSWAGEN","FERRARY","PORSCHE"]

const updated = [];
for (let i=1; i<=5; i++) {
        updated.push(cars[i]);
}

console.log(updated);

Rahul Bhobe · Accepted Answer · 2020-06-29T03:11:08.413

2

To do this in a loop for indexes 1 to 5 (inclusive):

let cars = ["AUDI","BMW","LEXUS","VOLKSWAGEN","FERRARY","PORSCHE"]

const filteredCars = [];
for (let i=1; i<=5; i++) {
        filteredCars.push(cars[i]);
}

console.log(filteredCars);

Without loop you may also use filter() or slice(). See example with filter():

let cars = ["AUDI","BMW","LEXUS","VOLKSWAGEN","FERRARY","PORSCHE"]

const filteredCars=cars.filter((item, i) => i>=1 && i<=5);

console.log(filteredCars);

edited Jun 29 '20 at 03:11

answered Jun 29 '20 at 01:15

Rahul Bhobe

4,165
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Thank you very much – Roffy bc Jun 29 '20 at 01:44
1

Why are you performing unnecessary iterations. `for (let i = 1; i <=5; i++)` seems more appropriate – Phil Jun 29 '20 at 01:44
Edited - Thanks – Rahul Bhobe Jun 29 '20 at 01:45

score 1 · Answer 4 · answered Jun 29 '20 at 02:03

You can do it with forEach :

let cars = ["AUDI","BMW","LEXUS","VOLKSWAGEN","FERRARY","PORSCHE"];

function repea (element, index) {
  console.log(`The current index is: ${index}`);
  console.log(`The current element is: ${element}`);
}


cars.forEach(repea);

Return items from array with index 1 to 5 Javascript

4 Answers4