When I'm using RequestDispatcher and using forward to send my my request and response to a new servlet I'm getting error

Question

When I'm running this program on the server I'm getting multiple errors. Added the XML code too, I think something is wrong with that.


<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
    xmlns="http://xmlns.jcp.org/xml/ns/javaee"
    xsi:schemaLocation="http://xmlns.jcp.org/xml/ns/javaee http://xmlns.jcp.org/xml/ns/javaee/web-app_4_0.xsd"
    id="WebApp_ID" version="4.0">

    <servlet>
        <servlet-name>abc</servlet-name>
        <servlet-class>com.shlok.AddServlet</servlet-class>
    </servlet>

    <servlet-mapping>
        <servlet-name>abc</servlet-name>
        <url-pattern>/add</url-pattern>
    </servlet-mapping>

    <servlet>
        <servlet-name>pqr</servlet-name>
        <servlet-class>com.shlok.SqServlet</servlet-class>
    </servlet>

    <servlet-mapping>
        <servlet-name>abc</servlet-name>
        <url-pattern>/sq</url-pattern>
    </servlet-mapping>

</web-app>
public class AddServlet extends HttpServlet {
    public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException, ServletException {
        int i = Integer.parseInt(req.getParameter("num1"));
        int j = Integer.parseInt(req.getParameter("num2"));

        int k = i + j;

        req.setAttribute("k", k);
        RequestDispatcher rd = req.getRequestDispatcher("sq");
        rd.forward(req, res);   
    }
}

public class SqServlet extends HttpServlet {
    public void doGet(HttpServletRequest req, HttpServletResponse res) throws IOException {

        int k = (int) req.getAttribute("k");
        k = k * k;

        PrintWriter out = res.getWriter();
        out.println("Result is : " + k);
    }
}

What are the servlet mappings for `AddServlet` and `SqServlet`? Please show the relevant section of `web.xml` or the `@WebServlet` annotations used. — Andreas, Jun 27 '20 at 10:43
It would seem that the `/sq` Servlet mapping is mapping to `AddServlet`, not `SqServlet`, very likely the result of a **copy/paste error**. — Andreas, Jun 27 '20 at 10:50
And hence you proved my guess correct. `/sq` is mapped to servlet `abc`, not servlet `pqr` as it should be. Which means that when `AddServlet` is invoked, it forwards to `"sq"`, which is mapped to `abc`, which invokes `AddServlet`, which forwards to `"sq"`, which is mapped to `abc`, which invokes `AddServlet`, which forwards to `"sq"`, which is mapped to `abc`, which invokes `AddServlet`, which forwards to `"sq"`, which is mapped to `abc`, which invokes `AddServlet`, which forwards to `"sq"`, which is mapped to `abc`, which invokes `AddServlet`, which fails with **`StackOverflowError`** — Andreas, Jun 27 '20 at 11:54

Arvind Kumar Avinash · Accepted Answer · 2020-06-27T11:33:27.327

There is a mistake in the following mapping:

<servlet-mapping>
    <servlet-name>abc</servlet-name>
    <url-pattern>/sq</url-pattern>
</servlet-mapping>

It should be

<servlet-mapping>
    <servlet-name>pqr</servlet-name>
    <url-pattern>/sq</url-pattern>
</servlet-mapping>

I have replaced abc with pqr which maps to com.shlok.SqServlet.

Instead of mapping the servlets in web.xml, you could also do it using annotation as follows:

@WebServlet("/add")
public class AddServlet extends HttpServlet {
    //...
}

@WebServlet("/sq")
public class SqServlet extends HttpServlet {
    //...
}

Note: Make sure to pass the value of num1 and num2 as request parameters while calling AddServlet as shown below; otherwise, you will face java.lang.NumberFormatException: null.

When I'm using RequestDispatcher and using forward to send my my request and response to a new servlet I'm getting error

1 Answers1