Why custom type of function can only use for declaration?

Asked Jun 27 '20 at 05:48

Active Jun 27 '20 at 06:23

Viewed 41 times

Can anyone explain why define type(both of typedef and using) can only for header, but can't use for implement?

using myfunc = void();

myfunc test; //this will be okay
myfunc test {} //this is wrong

P.S. GCC said error: function ‘void test()’ is initialized like a variable for myfunc test {}

edited Jun 27 '20 at 06:17

asked Jun 27 '20 at 05:48

Oh sorry, I changed it – Jun 27 '20 at 06:03
Why Visual C++ said typedef cannot use for define? – Jun 27 '20 at 06:04
typedef and using can be used for both header and implementation. Whatever problem you are having it's something different to what you think it is. – john Jun 27 '20 at 06:18
So how to make it valid? – Jun 27 '20 at 06:19
1

@AlanJian That depends entirely on what you are trying to do, which isn't clear to me. Can you explain what you are trying to do? – john Jun 27 '20 at 06:19
I just want to make it a void function called test by integrated type – Jun 27 '20 at 06:20
`void test_impl(){} myfunc test = test_impl;` – Mooing Duck Jun 27 '20 at 06:23
@MooingDuck Sorry, my compiler said function can't initialized like a variable – Jun 27 '20 at 06:26

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